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(X+2)^2=1-X(X+3)
We move all terms to the left:
(X+2)^2-(1-X(X+3))=0
We calculate terms in parentheses: -(1-X(X+3)), so:We get rid of parentheses
1-X(X+3)
determiningTheFunctionDomain -X(X+3)+1
We multiply parentheses
-X^2-3X+1
We add all the numbers together, and all the variables
-1X^2-3X+1
Back to the equation:
-(-1X^2-3X+1)
1X^2+3X+(X+2)^2-1=0
We add all the numbers together, and all the variables
X^2+3X+(X+2)^2-1=0
We move all terms containing X to the left, all other terms to the right
X^2+3X+(X+2)^2=1
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